12y^2+y=-11y

Solution for 12y^2+y=-11y equation:

12y^2+y=-11y

We move all terms to the left:

12y^2+y-(-11y)=0

We get rid of parentheses

12y^2+y+11y=0

We add all the numbers together, and all the variables

12y^2+12y=0

a = 12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·12·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*12}=\frac{-24}{24}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*12}=\frac{0}{24}
=0
$